Problema Solution
Find the length and width of a rectangle that has an area of 28ft squared and a length that is 3 more than its width.
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
A = 28 ft^2
the length is 3 more than its width:
l = w + 3
the area of the rectangle is A = l*w thus we have:
l*w = 28
plug l = w + 3 into the last equation:
(w + 3)w = 28
by solving we find:
w = 4 ft
click here to see the step by step solution of the equation:
l = w + 3
l = 4 + 3
l = 7 ft
the length is 7 ft and the width is 4 ft.