Problema Solution
The perimeter of a rectangular lot is 80. The length is 1 more than twice the width. Find the length and width
Answer provided by our tutors
let
l = the length of the rectangle
w = the width of the rectangle
P = 80 the perimeter
the length is 1 more than twice the width:
l = 1 + 2w
the perimeter of the rectangle P = 2(l + w) thus we have:
2(l + w) = 80 divide both sides by 2
l + w = 40
by solving the system of equations:
l = 1 + 2w
l + w = 40
we find:
l = 27
w = 13
click here to see the step by step solution of the system of equations:
the length is 27 and the width is 13.