Problema Solution
two planes, which are 3040 miles apart fly toward each other. Their speeds differ by 60 mph. if they pass each other in 4 hours, what is the speed of each?
Answer provided by our tutors
let
v = the speed of the first plane, v>0
v + 60 = the speed of the second plane (since the differ by 60 mph)
t = 4 hr the time of the flight
since speed = distance/time we have distance = speed*time
the distance the first plane made + the distance the second plane made = the total distance of 3040 miles
v*t + (v + 60)*t = 3040
v*4 + (v + 60)*4 = 3040
by solving we find:
v = 350 mph the speed of the first plane
click here to see the step by step solution of the equation:
350 + 60 = 410 mph the speed of the second plane.