Problema Solution
Find the dimensions of a rectangle whose area is 208 cm2 and whose perimeter is 58 cm
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
the perimeter of the rectangle is 58 means:
2(l + w) = 58 divide both sides by 2
l + w = 29
l = 29 - w
the area is 208 cm^2 means:
l*w = 208
plug l = 29 - w into the last equation:
(29 - w)*w = 208
by solving we find:
w1 = 13 cm
w2 = 16 cm
click here to see the step by step solution of the quadratic equation:
for w = 13 cm we have l = 29 - 13 = 16 cm
for w = 16 cm we have l = 29 - 16 = 13 cm
the dimensions of the rectangle are 13 cm and 16 cm.