Problema Solution
A parking meter contains dimes and quarters worth $7.10. There are 47 in all. Find how many of each there are
Answer provided by our tutors
1 dime = 10 cents
1 quarter = 25 cents
let
d = the number of dimes, d>0
q = the number of quarters, q>0
A parking meter contains dimes and quarters worth $7.10 = 710 cents:
10d + 25q = 710 divide both sides by 5
2d + 5d = 142
There are 47 in all:
d + n = 47
by solving the system of equations:
2d + 5q = 142
d + q = 47
we find:
d = 31 dimes
q = 16 quarters
click here to see the step by step solution of the system of equations:
there are 31 dimes and 16 quarters.