Problema Solution
pipes A and B can fill a storage tank in 8 hours and 12 hours, respectively. With the tank empty, pipe A has turned on at noon, and then pipe B turned on at 1:30PM. What Time was the tank full?
Answer provided by our tutors
the rate of pipe A is = 1/8 tank/hour
the rate of pipe B is = 1/12 tank/hour
t = the time A need to fill the tank, t>0
t - 1.5 = the time B needs to fill the tank
(1/8)t + (1/12)(t - 1.5) = 1
by solving we find:
t = 5.4 hr
t = 5 hr 0.4*60 min
t = 5 hr 24 min
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at 5:24 the tank will be full.