Problema Solution
A chemist wishes to mix some pure acid with some water to produce 16 L of a solution that is 30% acid. How much pure acid and how much water should be mixed?
Answer provided by our tutors
let
x = liters of pure 100% acid
y = liters of pure water (0% acid)
we need to produce 16 L of a solution that is 30% acid:
x + y = 16
1*x + 0*y = 0.30(x + y)
by solving we find:
x = 4.8 L
y = 11.2 L
click here to see the step by step solution of the system of equations:
4.8 liters of pure acid and 11.2 liters of water should be used for the mix.