Problema Solution

when fritz drives to work his trip takes 36 minutes but when he takes the train it takes 20 minutes. find the distance fritz travels to work if the train travels an average of 32 miles per hour faster that his driving

Answer provided by our tutors

let


t1 = 36/60 = 3/5 hr the time that Fritz drives to work


t2 = 20/60 = 1/3 hr the time that Fritx travels with the train to work


v1 = the average speed driving


v2 = the average speed with train


d = the distance


since v=d/t we have


v1 = d/t1


v1 = d/(3/5)


v1 = 5d/3


v2 = d/t2


v2 = d/(1/3)


v2 = 3d


the train travels an average of 32 miles per hour faster that his driving:


v2 = 32 + v1


plug v1 = 5d/3 and v2 = 3d into the last equation:


3d = 32 + 5d/3


by solving we find:


d = 24 mi


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the distance that Fritz travels to work is 24 miles.