Problema Solution
How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 15% antifreeze to get a mixture that is 50% antifreeze?
Answer provided by our tutors
let
x = gal of 60% antifreeze solution
0.60x + 0.15*90 = 0.50(x + 90)
by solving we find:
x = 315 gal
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315 gallons of the 60% antifreeze solutions should be used in the mixture.