Problema Solution
There are two airplanes: plane A and plane B. They travel in opposite directions and they leave an airport at the same time. One plane travels 65 km/h slower than the other. If the two planes are 3,438 km apart after 2 hours, what is the rate of each plane?
Answer provided by our tutors
let
v = the rate of the slower plane, v>0
v + 65 = the rate of the faster plane
t = 2 hr the time of the travel
d = 3,438 the distance between the two planes
since d = v*t and the planes travel in opposite direction:
the distance the first plane travels + the distance that the second plane travels = d
v*t + (v + 65)t = d
v*2 + (v + 65)2 = 3438
by solving we find:
v = 827 km/h
click here to see the step by step solution of the equation:
v + 65 = 827 + 65 = 892 km/h
the rates of the planes are 827 km/h and 892 km/h.