Problema Solution

A tourist can bicycle 28 miles in the same time as he can walk 8 miles. If he can ride 10 mph faster than he can walk, how much time should he allow to walk a 35-mile trail?

Answer provided by our tutors

let


v = the average speed of walking


v + 10 = the average speed of bicycling


since speed = distance/time follows time = distance/speed


v/8 = (v + 10)/28


by solving we find:


v = 4 mph


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35 miles the tourist will walk in: 35/4 = 8 3/4 hr = 8 hr 3*40/4 min = 8 hr 12 min.