Problema Solution
The length of a new rectangular playing field is 4 yards longer than quadruple the width, If the perimeter of the new rectangular playing field is 488 yards, what are its dimensions?
Answer provided by our tutors
let
l = the length of the field
w = the width of the field
the length of a new rectangular playing field is 4 yards longer than quadruple the width:
l = 4 + 4w
the perimeter of the new rectangular playing field is 488 yards:
2(l + w) = 488
by solving the system of equations:
l = 4 + 4w
2(l + w) = 488
we find:
l = 196 yd
w = 48 yd
click here to see the step by step solution of the system of equations:
the dimensions of the field are: the length is 196 yards and the width is 48 yards.