Problema Solution
Mike has $1.35 in dimes and nickels. If he has 6 more nickels than dimes, how many of each coin does he have?
Answer provided by our tutors
1 nickle = 5 cents
1 dime = 10 cents
let
n = the number of nickles, n>0
d = the number of dimes, d>0
Mike has $1.35 = 135 cents in dimes and nickels:
5n + 10d = 135
he has 6 more nickels than dimes:
n = d + 6
by solving the system of equations:
5n + 10d = 135
n = d + 6
we find:
n = 13 nickles
d = 7 dimes
click here to see the step by step solution of the system of equations:
Mike has 13 nickles and 7 dimes.