Problema Solution
Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 378 miles in the same time that Dana travels 354 miles. If Chuck's rate of travel is 4 mph more than Dana's, and they travel in the same length of time, at what speed does Chuck travel?
Answer provided by our tutors
let
v1 = Chuck's speed (rate)
v2 = Dana's speed (rate)
d1 = 378 mi the distance Chuck travels
d2 = 354 the distance Dana travels
t = the time of the travel
Chuck's rate of travel is 4 mph more than Dana's:
v1 = v2 + 4
v2 = 4 - v1
Chuck travels 378 miles in the same time that Dana travels 354 miles
since speed=distance/time we have
v1 = d1/t
t = d1/v1
v2 = d2/t
t = d2/v2
now we have
d1/v1 = d2/v2
378/v1 = 354/v2
plug v2 = 4 - v1 into the last equation:
378/v1 = 354/(4 - v1)
by solving we find:
v1 = 2.07 mph
click here to see the step by step solution of the equation:
Chuck's speed is 2.07 mph.