Problema Solution
The initial population of a town is 3800, and it grows with a doubling time of 10 years. what will the population be in 8 years
Answer provided by our tutors
The time required for each doubling in exponential growth is called the doubling time.
Simple doubling time formula:
N(t) = C*2^(t/d)
N(t) = the number of objects at time t
d = 10 years doubling period (time it takes for object to double in number)
c = 3,800 initial number of objects, in our case population
t = 8 years time
N(8) = 3800*2^(8/10)
N(8) = 6,616
click here to see the step by step calculation:
in 8 years the population will be 6,616.