Problema Solution
Derek is playing a board game with three number cubes. What is the probability of Derek rolling three of a kind or a sum that is an odd number?
Answer provided by our tutors
the formula for p(a or b) is:
p(a or b) = p(a) + p(b) - p(ab)
p(a) = the probability of rolling three of a kind:
P(a) = 6/(6^3) = 1/6^2
p(b) = the probability of rolling a sum that is an odd number:
p(b) = 1/2
p(ab) is the probability of both occurring at the same time, rolling 3 of a kind whose sum is an odd number:
p(ab) = 3/6^3
p(ab) = 1/(2*(6^2))
lets plug the values into
p(a or b) = p(a) + p(b) - p(ab)
p(a or b) = 1/6^2 + 1/2 - 1/(2*(6^2))
by calculating we find:
p(a or b) = 0.5139
click here to see the step by step calculation:
the probability of Derek rolling three of a kind or a sum that is an odd number is 0.5139.