Problema Solution
the ages of three family children can be expressed as consecutive integers. the square of the age of the youngest is four more than eight times the age of the oldest child. find the ages of the three children
Answer provided by our tutors
the ages of three family children can be expressed as consecutive integers:
x - 1, x and x, where x is integer, and x - 1 >0 that is x>1
the square of the age of the youngest is four more than eight times the age of the oldest child:
(x - 1)^2 = 4 + 8(x + 1)
by solving we find:
x = 11 years
click here to see the step by step solution of the equation:
11 - 1 = 10
11 + 1 = 12
the ages of the three children are 10, 11 and 12.