Problema Solution
One number is four less than a second number. Twice the first number 13 more than 5 times the second. Find the numbers.
Answer provided by our tutors
let
x = the first number
y = the second number
One number is four less than a second number:
x = y - 4
Twice the first number is 13 more than 5 times the second:
2x = 13 + 5y
by solving the system of equations:
x = y - 4
2x = 13 + 5y
we find:
x = -11
y = -7
click here to see the step by step solution of the system of equations:
the numbers are -11 and -7.