Problema Solution
Justin drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 6 hours. When Justin drove home, there was no traffic and the trip took 4 hours. If his average rate was 22 miles per hour faster on the trip home, how far away does Justin live from the mountians?
Answer provided by our tutors
let
v1 = the average rate on the way to the mountains
t1 = 6 hr the time of the trip to the mountains
v2 = the average rate on the way back from the mountains
t2 = 4 hr the time of the trip back from the mountains
d = the distance to the mountains
his average rate was 22 miles per hour faster on the trip home:
v2 = v1 + 22
since distance = speed*time we have:
d = v1*t1 = v2*t2
6v1 = 4v2
by solving the system of equations:
v2 = v1 + 22
6v1 = 4v2
we find:
v1 = 44 mph
v2 = 66 mph
click here to see the step by step solution of the system of equations:
d = v1*t1
d = 6*44
d = 264 mi
Justin lives 264 miles away from the mountains.