Problema Solution

Gabriella wants to tile a room with an area of 320 square feet. The width of the room is 4/5 its length. What are the length and width of the room?

Answer provided by our tutors

let


l = the length of the room, l>0


w = the width of the room, w>0


A = 320 ft^2 the area of the room


The width of the room is 4/5 its length:


w = (4/5)l


the area of the room A = l*w


l*w = 320


plug w = (4/5)l into the last equation:


l*(4/5)l = 320


by solving we find:


l = 20 ft


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w = (4/5)*20


w = 16 ft


the length is 20 ft and the width is 16 ft.