Problema Solution
A mixture of 40 L of alcohol and water contains 10% water. How much water should he added to this mixture so that the new mixture contains 20% water„?
Answer provided by our tutors
let 'x' represent the amount of water in liters
0.10*40 + 1.00*x = 0.20(40 + x)
by solving we find:
x = 5 L
click here to see the step by step solution of the equation:
5 liters of water should be added to the mixture.