Problema Solution
Use the formula
h = vt − 16t2,
where h is the height in feet that an object will attain (neglecting air resistance) in t seconds, and v is the initial velocity in feet per second.
A golf ball is thrown onto a cement surface and rebounds straight up. The initial velocity of the rebound is 32 ft/s. How many seconds later will the golf ball return to the ground?
Answer provided by our tutors
h = vt − 16t^2
v = 32 ft/s
t = the time when the golf ball returns to the ground that is h = 0
h = 0
32t − 16t^2 = 0
by solving we find:
t = 2 s
click here to see the step by step solution of the equation:
the golf ball will return to the ground in 2 seconds.