Problema Solution

How much water must be added to 1 liter of 37% solution to yield an 11% solution?

Answer provided by our tutors

The solution is currently 1 L with a concentration of 37%

This means there are 37 parts per 100 mL of solution, and the solution is 1 L (1000 mL) so there are 37 * (1000 mL / 100 mL) = 370 total parts in the solution.

To yield an 11% solution, we want 11 parts per 100 mL of solution. Since we have 370 parts, we need 370 / 11 * (100 mL) of total solution, which is equal to 3363.6 mL = 3.3636 L.

Since we already have 1 L, we need to add 3.3636 L - 1 L = 2.3636 L of water to the solution.