Problema Solution
The Johnson family is building a dog house. The total floor-surface area will be 24 sq ft. If the length is 6 more than three times the width, what is the width of the dog house?
Answer provided by our tutors
we will assume the house is rectangular
let
l = the length of the house, l>0
w = the width of the house, w>0
A = 24 ft^2
the length is 6 more than three times the width:
l = 6 + 3w
the area of rectangle is width*length that is A = l*w
l*w = 24
plug l = 6 + 3w into the last equation:
(6 + 3w)w = 24
by solving we find:
w = 2 ft
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the width of the dog house is 2 ft.