Problema Solution
A soda is placed in a refrigirator. The temperature of the soda after t minutes in the refrigerator is described by the function: s(t)=36+34e^-0.021t. Based on the model, what will be the temperature of the soda after 2 hours?
Answer provided by our tutors
t = 2 hr
t = 2*60 min
t = 120 min
we plug t = 120 into s(t)=36+34e^-0.021t and get:
s(120)=36+34e^(-0.021*120)
e = 2.72
s(120) = 36+34*2.72^(-0.021*120)
s(120) = 38.73
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