Problema Solution
Lines s passes through the points (2,7) and (6,1). Line t passes through the point (5,2) and perpendicular to the line s. What is the equation for line t
Answer provided by our tutors
the slope m1 of the line s that passes through the points (2,7) and (6,1) is:
m1 = (1 - 7)/(6 - 2)
m1 = - 6/4
m1 = -3/2
the slope m2 of line t perpendicular to line s is:
m1*m2 = -1
(-3/2)*m2 = -1
m2 = 2/3
the equation of line t can be written as: y = m2*x + b2, where b2 is the y-intercept
y = (2/3)*x + b2
since the line goes trough (5,2) we have:
2 = (2/3)*5 + b2
by solving we find:
b2 = -4/3
click here to see the step by step solution of the equation:
the equation of line t is: y = (2/3)x - (4/3).