Problema Solution

In 2010, hourly wages for the top three CEOs of U.S. corporations were calculated based on their working 14 hours per day for 365 days. Together the three CEOs made $75,000 per hour. The first CEO earned $3,000 more per hour than the hourly wage of the second CEO, and the first CEO earned $6,000 more per hour than the third CEO. Determine the hourly wages of each CEO

Answer provided by our tutors

let


x = the hourly wage of the first CEO


y = the hourly wage of the second CEO


z = the hourly wage of the third CEO


Together the three CEOs made $75,000 per hour:


x + y + z = 75000


the first CEO earned $3,000 more per hour than the hourly wage of the second CEO:


x = y + 3000


the first CEO earned $6,000 more per hour than the third CEO:


x = z + 6000


by solving the system of equations:


x + y + z = 75000


x = y + 3000


x = z + 6000


we find:


x = $28,000 per hour


y = $25,000 per hour


z = $22,000 per hour


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the first CEO had an hourly wage of $28,000 per hour.


the second CEO had an hourly wage of $25,000 per hour.


the third CEO had an hourly wage of $22,000 per hour.