Problema Solution
A train leaves New York for Boston, 200 miles away, at 4:00 P.M. and averages 55 mph. Another train leaves Boston for New York on an adjacent set of tracks at 3:00 P.M. and averages 60 mph. At what time will the trains meet? (Round to the nearest minute.)
Answer provided by our tutors
let
d = 200 mi the distance between New York and Boston
v1 = 55 mph the speed of the train from New York to Boston
t = the time of the travel of the train from New York till they meet
v2 = 60 mph the speed of the train from Boston to New York
t + 1 = the time of the travel of the train from Boston till they meet
since speed = distance/time follows distance = speed*time:
v1t + v2(t + 1) = d
55t + 60(t + 1) = 200
by solving we find:
t = 28/23
t = 1 5/23 hr
t = 1 hr 2*60/23
t = 1 hr 5 min
click here to see the step by step solution of the equation:
the trains will meet at 5:01 P.M.
let
d = 200 mi the distance between New York and Boston
v1 = 55 mph the speed of the train from New York to Boston
t = the time of the travel of the train from New York till they meet
v2 = 60 mph the speed of the train from Boston to New York
t + 1 = the time of the travel of the train from Boston till they meet
since speed = distance/time follows distance = speed*time:
v1t + v2(t + 1) = d
55t + 60(t + 1) = 200
by solving we find:
t = 28/23
t = 1 5/23 hr
t = 1 hr 2*60/23
t = 1 hr 5 min
click here to see the step by step solution of the equation:
the trains will meet at 5:05 P.M.