Problema Solution
a man is twice as old as his son. twenty year ago, the father was 4 time as old as the son. find the present age of each.
Answer provided by our tutors
let
m = the present age of the man
s = the present age of the son
a man is twice as old as his son:
m = 2s
twenty year ago, the father was 4 time as old as the son:
m - 20 = 4(s - 20)
by solving the system of equations:
m = 2s
m - 20 = 4(s - 20)
we find:
m = 60 years
s = 30 years
click here to see the step by step solution of the system of equations:
the present age of the father is 60 years.
the present age of the son is 30 years.