Problema Solution
How many positive four-digit integers have 2 as their second digit and 3, 4, or 7 as their last digit?
Answer provided by our tutors
the first digit can be any number from 1 to 9 but not 0 (9 options)
the second digit is 2 (1 option)
the third digit can be any number from 0 to 9 (10 options)
the last digit can be 3, 4 or 7 (3 options)
thus there are 9*1*10*3 = 1270 positive four-digit integers have 2 as their second digit and 3, 4, or 7 as their last digit.
the first digit can be any number from 1 to 9 but not 0 (9 options)
the second digit is 2 (1 option)
the third digit can be any number from 0 to 9 (10 options)
the last digit can be 3, 4 or 7 (3 options)
thus there are 9*1*10*3 = 270 positive four-digit integers have 2 as their second digit and 3, 4, or 7 as their last digit.