Problema Solution

what distance does a runner cover if he an acceleration of 1.32m/s/s and a final velocity of 11.1m/s and he runs for 9 secondswhat distance does a runner cover if he an acceleration of 1.32m/s/s and a final velocity of 11.1m/s and he runs for 9 seconds

Answer provided by our tutors

let


a = 1.32 m/s^2


v = 11.1 initial velocity


t = 9 s


d = the distance


d = vt + (1/2)at^2


d = 11.1*9 + (1/2)*1.32*9^2


d = 153.36 m


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the runner covers a distance of 153.36 meters.