Problema Solution
Write a system of two equations in two variables to solve the problem.
How much of a 40% antifreeze solution must a mechanic mix with an 80% antifreeze solution if 12 gallons of a 50% antifreeze solution are needed?
Answer provided by our tutors
let
x = gal of the 40% antifreeze solution
y = gal of the 80% antifreeze solution
0.40x + 0.80y = 0.50*12
x + y = 12
by solving we find:
x = 9 gal
y = 3 gal
click here to see the step by step solution of the system of equations:
9 gallons of 40% antifreeze solution must be mixed with 3 gallons of 80% antifreeze solution.