Problema Solution
A chemist has two alloys, one of which is 15% gold and 10% lead and the other which is 30% gold and 40% lead. How many grams of each of the two alloys should be used to make an alloy that contains 88.5 g of gold and 77 g of lead?
Answer provided by our tutors
let
x = g of the first alloy which is 15% gold and 10% lead
y = g of the second alloy which is 30% gold and 40% lead
0.15x + 0.30y = 88.5
0.10x + 0.40y = 77
by solving the above system of equations we find:
x = 410 g
y = 90 g
click here to see the step by step solution of the system of equations:
410 g of the first and 90 g of the second alloy should be used.