Problema Solution
Vinay and Sadiva leave the same location traveling the same route, but Sadiva leaves 20 minutes after Vinay. If Vinay drives 30 mph and Sadiva drives 36 mph, how long will it take Sadiva to catch Vinay?
Answer provided by our tutors
let
v1 = 30 mph the rate of Vinay
v2 = 36 mph the rate of Sadiva
t = the time of Sadiva, t>0
t + 20/60 = t + 1/3 the time of Vinay
since speed = distance/time follows distance = speed*time
v1(t + 1/3) = v2*t
30(t + 1/3) = 36t
by solving we find:
t = 5/3 hr
t = 1 hr 2*60/3 min
t = 1 hr 40 min
click here to see the step by step solution of the equation:
Sadiva will catch Vinay after 1 hour and 40 minutes.