Problema Solution
Arnold had $1.70 in dimes and quarters. He had 3 more dimes than quarters. How many of each type did he have?
Answer provided by our tutors
1 quarter = 25 cents
1 dime = 10 cents
let
q = the number of quarters, q>=0, q is integer
d = the number of dimes, d>=0, d is integer
Arnold had $1.70 = 170 cents in dimes and quarters:
10d + 25q = 170
He had 3 more dimes than quarters:
d = q + 3
by solving the system of equations:
10d + 25q = 170
d = q + 3
we find:
d = 7 dime
q = 4 quarters
click here to see the step by step solution of the system of equations:
Arnold has 7 dimes and 4 quarters.