Problema Solution
At 1:30pm two planes leave chicago, one flyying east at 540 mph and the other flying west at 80 mph faster than the other plane. At what time will they be 1450 miles apart?
Answer provided by our tutors
let
v1 = 540 mph the rate of the plane flying east
v2 = 540 + 80 = 620 mph the rate of the plane flying west
t = the time of the flight until they are 1450 mi apart
v1t + v2t = 1450
t*(v1 + v2) = 1450
t*(540 + 620) = 1450
by solving we find:
t = 1.25 hr
t = 1 hr 0.25*60 min
t = 1 hr 15 min
click here to see the step by step solution of the equation:
1 hr 15 min after 1:30 pm is 2:45 pm
at 2:45 pm the planes will be 1450 miles apart.