Problema Solution
find 3 consecutive integers such that the square of the sum of the lesser two is equal to twice the greatest
Answer provided by our tutors
the 3 consecutive integers can be written as:
x-1, x and x+1, where x is integer
the square of the sum of the lesser two is equal to twice the greatest
(x-1 + x)^2 = 2(x + 1)
by solving we find:
x1 = 1.65
x2 = -0.15
click here to see the step by step solution of the equation:
since the solutions are not integers we conclude that there are no such 3 consecutive integers.