Problema Solution

find 3 consecutive integers such that the square of the sum of the lesser two is equal to twice the greatest

Answer provided by our tutors

the 3 consecutive integers can be written as:


x-1, x and x+1, where x is integer


the square of the sum of the lesser two is equal to twice the greatest


(x-1 + x)^2 = 2(x + 1)


by solving we find:


x1 = 1.65


x2 = -0.15


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since the solutions are not integers we conclude that there are no such 3 consecutive integers.