Problema Solution
IF THE PERIMETER OF A RECTANGULAR PIECE OF GLASS IS 26 INCHES AND THE LENGTH IS 4 INCHES LONGER THAN TWICE THE WIDTH, THEN WHAT ARE THE LENGTH AND WIDTH?
Answer provided by our tutors
let
P = 26 in the perimeter of the rectangle
w = the width of the rectangle, w>0
l = the length of the rectangle, l>0
THE LENGTH IS 4 INCHES LONGER THAN TWICE THE WIDTH:
l = 4 + 2w
the perimeter P = 2(l + w) thus
2(l + w) = 26 divide both sides by 2
l + w = 13
by solving the system of equations:
l = 4 + 2w
l + w = 13
we find:
l = 10 in
w = 3 in
click here to see the step by step solution of the system of equations:
the length is 1o inches.
the width is 3 inches.