Problema Solution
How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?
Answer provided by our tutors
let
x = liters of pure water
0*x + 0.25*10 = 0.10(x + 10)
by solving we find:
x = 15 L
click here to see the step by step solution of the equation:
15 liters of pure water must be used for the mix.