Problema Solution
The radioactive element has a half-life of 432 years. start with 20-g mass. how much will be left after 367 years?
Answer provided by our tutors
The amount A of the radioactive material present at a time t is given by the model
A = A0*(1/2)^(t/h)
where A0 is the amount present initially, h is the half-life of the material.
In our case we have
A0 = 20 g
h = 432 years half-life
t = 367 years
A = 20*(1/2)^(367/432)
by solving we find
A = 11.1 g
click here to see the step by step calculation:
there will be 11.1 grams left after 367 years.