Problema Solution

Bob's age is 4 times greater than Susanne's age. Dakota is three years younger than Susanne. The sum of Bob's, Susanne's, and Dakota's ages is 93. What is Susanne's age?

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let


b = Bob's age


s = Susanne's age


d = Dakota's age


Bob's age is 4 times greater than Susanne's age:


b = 4s


Dakota is three years younger than Susanne:


d = s - 3


The sum of Bob's, Susanne's, and Dakota's ages is 93:


b + s + d = 93


by solving the system of equations:


b = 4s


d = s - 3


b + s + d = 93


we find:


b = 64 years


s = 16 years


d = 13 years


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Susanne is 16 years.