Problema Solution
The length of a rectangle is 1yd more than twice its width, and the area of the rectangle is 28yd^2 . Find the dimensions of the rectangle.
Answer provided by our tutors
(2x+1)(x)=28
2x^2 + x - 28 = 0
2x^2 + 8x - 7x - 28 = 0
2x(x+4)-7(x+4)=0
(2x-7)(x+4)=0
x=7/2
x=-4
x=7/2
width is 7/2
lenght is 2(7/2) + 1 = 8