Problema Solution
Two isosceles triangles have equal vertical angles and their corresponding sides are in the ratio of 3 : 7. What is the ratio of the areas?
Answer provided by our tutors
for the first triangle we can write:
3x = the length of the side
3h = the height corresponding the the side
the area of the first triangle is:
A1 = (1/2) 3x*3h
A1 = (1/2)*9*xh
for the second triangle now we have:
7x = the length of the side
7h = the height corresponding the the side
the area of the second triangle is:
A2 = (1/2)*7x*7h
A2 = (1/2)*49*xh
A1 : A2 = ((1/2)*9*xh) : ((1/2)*49*xh) = 9 : 49
the ratio of the areas is 9 : 49.