Problema Solution
the perimeter of a rectangle is 62 m. The length is four more than two times the width. What is the length?
Answer provided by our tutors
let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
P = 62 m the perimeter of the rectangle
The length is four more than two times the width:
l = 4 + 2w
The perimeter P = 2(l + w)
2(l + w) = 62 divide both sides by 2
l + w = 31
by solving the system of equations:
l = 4 + 2w
l + w = 31
we find:
l = 22 m
w = 9 m
click here to see the step by step solution of the system of equations:
the length is 22 meters.