Problema Solution
A non-zero fraction's denominator is increased by 1 and its numerator is decreased by 50%. If the resulting fraction is 1/3 of the original fraction, what is the original fraction's denominator?
Answer provided by our tutors
let
x = the original fraction's denominator, x<>0
y = the original fraction's numerator
y/x = the original fraction
A non-zero fraction's denominator is increased by 1 and its numerator is decreased by 50% and the resulting fraction is 1/3 of the original fraction:
y(1 - 0.50)/(x + 1) = (1/3)(y/x)
by solving we find:
x = 2
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the original fraction's denominator is 2.