Problema Solution

the perimeter of a rectangle is 38 feet. the length is 17 feet less than five times the width. what are the dimensions of the rectangle

Answer provided by our tutors

let


l = the length of the rectangle


w = the width of the rectangle


P = 38 ft the perimeter of the rectangle


2(l + w) = 38


the length is 17 feet less than five times the width:


l = 5w - 17


by solving the system of equations:


2(l + w) = 38


l = 5w - 17


we find:


l = 13 ft


w = 6 ft


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the dimensions of the rectangle are: the length is 13 ft and the width is 6 ft.