Problema Solution

determine the points of intersection of curve y^2-10x+10y-55=0 and a line 2x-y-10=0

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from 2x-y-10=0 follows y = 2x - 10


plug y = 2x - 10 into y^2-10x+10y-55=0


(2x - 10)^2 - 10x + 10(2x - 10) - 55 = 0


by solving we find:


x1 = 9.02


x2 = -1.52


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for x1 = 9.02 we have y1 = 2*9.02 - 10 = 8.04


for x2 = -1.52 we have y2 = 2*(-1.52) - 10 = -13.04


the points of intersection are: (9.02, 8.04) and (-1.52, -13.04).