Problema Solution

The perimeter of the basketball court is 288 ft. The length is 40 ft. longer than the width. Find the dimensions of the court.

What is the width? Simplified

What is the length? Simplified

Answer provided by our tutors

let


l = the length of the court, l>0


w = the width of the court, w>0


P = 288 ft the perimeter


P = 2(l + w) thus


2(l + w) = 288 divide both sides by 2


l + w = 144


the length is 40 ft. longer than the width:


l = w + 40


by solving the system of equations:


l + w = 144


l = w + 40


we find:


l = 92 ft


w = 52 ft


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the width is 52 feet.


the length is 92 feet.