Problema Solution
a rectangular swimming pool is twice as long as it is wide. a small, decorative, non-slip walkway surrounds the pool. the walkway is a constant 2 feet wide and has area of 196 square feet. find the dimension of the pool.
Answer provided by our tutors
let
w = the width of the pool, w>0
l = the length of the pool, l>0
a = 2 ft the width of the walkaway
the area of the walkaway = the total area together with walkaway - the area of the pool without walkaway
196 = (w + 2a)(l + 2a) - w*l
(w + 2*2)(l + 2*2) - w*l = 196
a rectangular swimming pool is twice as long as it is wide:
l = 2w
plug l = 2w into (w + 2*2)(l + 2*2) - w*l = 196
(w + 2*2)(2w + 2*2) - w*2w = 196
by solving we find:
w = 15 ft
click here to see the step by step solution of the equation:
l = 2*15
l = 30 ft
the dimensions of the pool are: the length is 30 ft and the width is 15 ft.