Problema Solution

Suppose you want to draw a rectangle where the width is 7 inches less than the length and the diagonal is 7 inches longer than the length. What are the dimensions of the rectangle?

Answer provided by our tutors

let


x = represent the length, x>=0


x - 7 = the width, x - t >=0, x>= 7


x + 7 = the diagonal


using the Pythagorean Theorem we have:


x^2 + (x - 7)^2 = (x + 7)^2


by solving we find:


x = 28 in


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x - 7 = 28 - 7 = 21 in


the dimensions of the rectangle are: 28 in and 21 in.